https://issues.apache.org/bugzilla/show_bug.cgi?id=51197
--- Comment #7 from Christopher Schultz <ch...@christopherschultz.net> 2012-02-21 16:48:05 UTC --- Konstantin, (In reply to comment #5) > The > URLConnection used to implement getUrl() cannot read content if response code > is >= 400.If I remove status code check in TomcatBaseTest#getUrl() to always > read response text regardless of status code, it just fails with an > IOException: You have to use URLConnection.getErrorStream if the response code is "problematic". I have this code in a class that fetches data from an HTTP server: int responseCode = conn.getResponseCode(); boolean error = 5 == responseCode / 100 || 4 == responseCode / 100; if(error) in = new BufferedInputStream(conn.getErrorStream()); else in = new BufferedInputStream(conn.getInputStream()); Then I just use "in" as I please. > Caused by: java.io.IOException: Server returned HTTP response code: 400 for > URL: http://localhost:3596/asyncErrorServlet > at > sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1436) > at java.net.HttpURLConnection.getResponseCode(HttpURLConnection.java:379) > at > org.apache.catalina.startup.TomcatBaseTest.getUrl(TomcatBaseTest.java:232) > ]]] Weird that it's throwing an exception from getResponseCode. What JRE are you using? -- Configure bugmail: https://issues.apache.org/bugzilla/userprefs.cgi?tab=email ------- You are receiving this mail because: ------- You are the assignee for the bug. --------------------------------------------------------------------- To unsubscribe, e-mail: dev-unsubscr...@tomcat.apache.org For additional commands, e-mail: dev-h...@tomcat.apache.org