https://issues.apache.org/bugzilla/show_bug.cgi?id=52579
Bug #: 52579
Summary: Tomcat5.5.35＋Java1.5 cannot return proper value of a
request parameter
Product: Tomcat 5
Version: 5.5.35
Platform: All
OS/Version: All
Status: NEW
Severity: regression
Priority: P2
Component: Connector:HTTP
AssignedTo: dev@tomcat.apache.org
ReportedBy: hayashi...@nttdata.co.jp
Classification: Unclassified
Created attachment 28251
--> https://issues.apache.org/bugzilla/attachment.cgi?id=28251
JSP file to reproduce the matter
(1) Overview
When I install Tomcat5.5.35＋jdk1.5.0_22 and run the JSP(please see the attached
document),
I cannot get proper value of a request parameter.
I enter multibyte character (e.g. 10 or aa) into the textbox of the JSP,
it runs correcly and i can get the input value (e.g. 10 or aa).
But I enter 1 byte character (e.g. "1" or "a"),
it runs incorrectly and i can get nothing.
Please advise me.
(Our customers are also waiting for the reason.)
Thank you.
(2) Steps to Reproduce
[2-1] Install Tomcat5.5.35＋jdk1.5.0_22
[2-2] Deploy the JSP file in the following directory.
/apache-tomcat-5.5.35/webapps/jsp-examples
[2-3] Enter the 1 byte character (e.g. "1" or "0") to the textbox and push ok
button.
(3) Actual Results
The "message" shows nothing.
(4) Expected Results
The "message" shows the input character.
(5) Build Date & Platform
Build 2012-02-02 on Windows7
(I suppose it does not depend on the Platform.)
(6) Additional Information
Tomcat5.5.34＋jdk1.5.0_22 runs correctly.
So the following codes may be the reason:
---
org.apache.tomcat.util.buf.ByteChunk.toStringInternal()
# Line514
CharBuffer cb;
cb = charset.decode(ByteBuffer.wrap(buff, start, end-start));
return new String(cb.array(), cb.arrayOffset(), cb.length());
---
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