**
What happens if PatternSyntaxException is thrown? (bad regex is passed in)
While it is a RuntimeException - i'd assume you'd want to log.warn(with the
regex) and return -1;


-Tim

On 6/15/2011 6:44 PM, ma...@apache.org wrote:

Modified: tomcat/trunk/java/org/apache/catalina/ssi/ExpressionParseTree.java
URL: 
http://svn.apache.org/viewvc/tomcat/trunk/java/org/apache/catalina/ssi/ExpressionParseTree.java?rev=1136231&r1=1136230&r2=1136231&view=diff
==============================================================================
@@ -350,6 +351,21 @@ public class ExpressionParseTree {
         protected int compareBranches() {
             String val1 = ((StringNode)left).getValue();
             String val2 = ((StringNode)right).getValue();
+
+            int val2Len = val2.length();
+            if (val2Len > 1 && val2.charAt(0) == '/' &&
+                    val2.charAt(val2Len - 1) == '/') {
+                // Treat as a regular expression
+                String expr = val2.substring(1, val2Len - 1);
+                Pattern pattern = Pattern.compile(expr);
+                // Regular expressions will only ever be used with EqualNode
+                // so return zero for equal and non-zero for not equal
+                if (pattern.matcher(val1).find()) {
+                    return 0;
+                } else {
+                    return -1;
+                }
+            }

Reply via email to