On Tue, Dec 03, 2019 at 05:54:33AM -0500, Rh Kramer wrote: > locate --regex \/\.gitignore
Your quoting is all wrong here. What you want is: locate --regex '/\.gitignore' The / does not need to be quoted, either for the shell, or for the regex. It's just a regular old character with no special meaning. The . on the other hand DOES need to be quoted, not for the shell, but for the regex. Because in a regex, it means "any character". Within the regex, you quote it by putting a \ in front of it. However, then that backslash needs to be quoted for the SHELL, because otherwise the shell interprets it: wooledg:~$ echo \. . See, that's not what you want. You need to pass the payload /\.gitignore as the regex, so you need to quote that in such a way that the shell doesn't screw with it. Thus, the single quotes around it. wooledg:~$ echo '/\.gitignore' /\.gitignore > But I've had no luck finding only the paths that end in .git. locate --regex '\.git$' Again, the single quotes protect the regex from interpretation by the shell.
