lina wrote: > Bob Proulx wrote: > > lina wrote: > >> aaa > >> model 0 > >> bbb > >> ddd > >> model 1 > >> ccc > >> > >> I want to print out the parts which match the "model 0" and ends with > >> match "model 1" > >> > >> for the final expected output is: > >> > >> model 0 > >> bbb > >> ddd > > > > Try this: > > > > sed -n '/^model 1/q;/^model 0/,$p' > > Just realize the sed -n '/model 0/,/model 1/'p can also do that. (so > newbie I was/am).
Not quite. You said you wanted the output to include the model 0 line but NOT the model 1 line. Doing /model 0/,/model 1/p prints both of the model lines including the model 1 line. The way I did it won't. > just still don't understand above sentence. sed -n '/^model 1/q;/^model 0/,$p' By default sed will print lines at the end of the processing loop. The -n option tells sed not to print lines by default. Otherwise every line would be printed. Then for the lines you want to print there is the explicit 'p' option to print that line.[1] Using /model 0/,/model 1/ means print the lines starting on the first pattern and ending on the second pattern. This prints the lines between along with the starting and ending lines. To avoid printing the ending pattern I did it differently. Let's look at the second part first. /^model 0/,$p says to print from the model line all of the way to the end of file. The end of file is designated by the '$' which is a line number and $ means the last line in the file when sed reads EOF from the file. I don't know how long the file will be so just print all lines starting with /^model 0/. Then to stop the printing where I want I use /^model 1/q which tells sed that when it sees the model 1 line that it should quit (exit) and when it exits it will of course no longer be printing. The exit clause must come before the printing clause so that it won't print the line that you didn't want printed. If they were in the other order then it would print the closing pattern line and then execute the exit clause. Normally sed will recycle the pattern. If you have multiple strings then it will reset and print the next set. $ printf "a\nb\nCCC\nd\ne\na\nb\nCCC\nd\ne\n" a b CCC d e a b CCC d e $ printf "a\nb\nCCC\nd\ne\na\nb\nCCC\nd\ne\n" | sed -n '/b/,/d/p' b CCC d b CCC d See how it reset above? But if you only want to print the first set then you would still want to 'q' to quit the program early. $ printf "a\nb\nCCC\nd\ne\na\nb\nCCC\nd\ne\n" | sed -n '/b/,/d/p;/d/q' b CCC d Hope that helps, Bob [1] GNU sed has a bug making it slightly incompatible with the classic Unix sed program. In Unix sed if you use 'p' without -n the line is only printed once. On HP-UX (System V sed) for example: $ echo hello | sed p hello In GNU sed it by default always prints and if there is a command to print then it prints the line again. $ echo hello | sed p hello hello For portable use never use p without also using -n to avoid duplicated lines and use that would not be the same on a traditional Unix system.
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