Jon Dowland wrote:
> On Thu, Jan 07, 2010 at 03:38:23PM +0530, Foss User wrote:
>> I want to do some operation on each file ending with .txt. However,
>> this script wouldn't work because in each iteration it gets one word
>> from the output of find.
>
> Did you read my reply to your last question?
> <http://lists.debian.org/debian-user/2010/01/msg00403.html>
>
> Look at the -print0 arg for find and the -0 argument for
> xargs.
Doesn't work - bash and the 'for' loop work on newline terminated
strings and don't know how to handle the null terminator from -print0:
$ find . -name '*txt'
./a b/tst.txt
./c/tst2.txt
$ for n in $(find . -name '*txt')
> do
> echo $n
> done
./a
b/tst.txt
./c/tst2.txt
$ for n in $(find . -name '*txt' -print0)
> do
> echo $n
> done
./a
b/tst.txt
$
In the third 'find' command with -print0, only one file is found, and it
is still split on the space.
>
>> Script:
>>
>> for file in `find -name "*.txt"`
>> do
>> echo file: $file
>> done
>
> You need to quote $file here:
> echo file: "$file"
>
> As described in another reply to your last thread,
> <http://lists.debian.org/debian-user/2010/01/msg00267.html>
>
> Please ensure you carefully read the replies people have
> already written.
>
>
Generally a good idea to quote the variable, but in this case it won't
help, the split on spaces has happened before the arguments get to the
'echo'.
I would suggest to the OP that they use a 'while' loop rather than 'for':
find . -name '*txt' |
while read n
do
echo "$n"
done
./a b/tst.txt
./c/tst2.txt
The 'read' gets the whole line, ignoring spaces.
--
Bob McGowan
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