On Wed, Dec 09, 2009 at 07:46:04PM +0000, Chris Jackson wrote: > lee wrote: > > >On Wed, Dec 09, 2009 at 07:07:52PM +0000, Chris Jackson wrote: > >> > >>Note that from the shell this is in single quote marks to stop shell > >>expansions. Doing it without those would be masochism ;) > > > >It already is: > > > > > >l...@yun:~/tmp/chan$ cat channels.dvb | sed '/^[^|]*|[^|]*-[0-9]|/' | wc -l > >sed: -e Ausdruck #1, Zeichen 21: Fehlender Befehl > >0 > >l...@yun:~/tmp/chan$ > > > > > >(which means: "expression #1, character 21: missing command" --- and > >it matches every line) > > > >But the idea behind your version is interesting :) > > > Well, you need to give it a command, I just gave you the regex. And > the default in sed is to print every line. Try:
Ah, I overlooked that! It seems to work! It should have been obvious, but I rarely use sed because it's so hard, but in this case, I thought I'd give it a try rather than writing a C program to do it. Thanks! -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org
