On Wed, Mar 25, 2009 at 04:25:45PM +0000, T o n g (mlist4sunt...@yahoo.com) wrote:
> I know we can put day of the week info as cron schedules, but how can I > define: Cron syntax can't handle these, but with an extra test in crontab they can be done. Assuming you want to run "myprog" at noon: > - first Monday of the month 0 12 * * 1 [ `date +%d` -le 7 ] && myprog or 0 12 1-7 * * [ `date +%w` = 1 ] && myprog > - second Monday of the month 0 12 8-14 * * [ `date +%w` = 1 ] && myprog > - last Monday of the month 0 12 * * * 1 [ "`date +%m`" != "`date --date week +%m`" ] && myprog The last depends on Gnu date (but that's what Debian uses, so it's appropriate here): "date --date week" gives the date one week from now, and if the month is different, today is the last Monday. -- Tapani Tarvainen -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org
