El(On) 28/06/2003 (15:03:27), David selby escribió(wrote): > Hello, > > I am writing bash a bash & sed script, it has been going suprisingly > well. I need a loop to count 9 times & the variable n to the count .. > > for n=1 to 9 > .... > next > > kind of thing, but this is not BASIC !! > > My best guess is > > declare -i n=1 > while [ $n < 9 ]; do > ..... > n=$((n+=1)) > done > > All i get is ... > > [EMAIL PROTECTED]:/usr/local/myfiles/dave/websites/kcards$ ./gensite > ./gensite: 9: No such file or directory > > I have defined it as an integer, used the less than operator for > integers, ... errr ... I know its something stupid but I can't crack it .... > > Dave > > PS is there a more ellagent way to do a counted loop as well as a way > that works ?
Perhaps you can use:
for n in `seq 1 9`; do
...
done
Regards.
--
______________________________________________________
______ _____________
Marcelo Ramos | \/ __ |
Debian Sid GNU/Linux 2.4.21 | |_/ /
Socio UYLUG Nro 125 | \
Linux registered user #118109 |_____|\/|_____|\______\
pgp00000.pgp
Description: PGP signature
