On Tue, 2005-07-05 at 18:53 -0400, Paul Smith wrote:
> %% Dexter <[EMAIL PROTECTED]> writes:
>
> d> But I want to use bash function instead of command.
>
> You can't.
>
> d> Problem is not, that command "find" runs in different environment, and
> d> doesn't know variables and functions from parent shell.
>
> Yes it is.
>
> d> Because i tried:
> d> A="XXX"
> d> $find . -exec echo $A \;
> d> XXX
>
> That example is not testing the right thing, because $A is expanded by
> your shell before find is invoked. In order to see if it's really
> working you'd have to escape it so that $A itself is passed to find,
> like this:
>
> find . -exec echo '$A' \;
> $A
> $A
> $A
>
> etc.
>
> d> And I also tried:
> d> export -f functionname(){
> d> .....
> d> }
>
> d> Somebody has a idea how to run function there?
>
> You can't.
>
> The problem is find -exec isn't running a shell at all; it's running
> that command directly by using fork/exec. Shell operations don't work
> there.
>
> Your only possibility of using a shell script is to run a shell as the
> exec command, something like:
>
> find . -exec /bin/bash -c "your script here" \;
>
> You'll need to check the bash man page to make sure that the function
> definition is put into the right file so that it's read when the shell
> starts this way (this is a non-interactive, non-login shell).
>
>
> Far simpler is to just write a shell script instead of using a function,
> or even use a different method of scripting; maybe something like:
>
> find . | while read file; do <do something with $file>; done
This line do, what i need.
>
> --
> -------------------------------------------------------------------------------
> Paul D. Smith <[EMAIL PROTECTED]> HASMAT--HA Software Mthds & Tools
> "Please remain calm...I may be mad, but I am a professional." --Mad Scientist
> -------------------------------------------------------------------------------
> These are my opinions---Nortel Networks takes no responsibility for them.
>
>
I tried before something like:
F=$(find .);for I in $F;do <do something with $I>; done
But, if there were spaces in files names, it broke file name on parts.
That is why I tried to call function from "find" command.
Thanks for help
Dexter
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