Is it perfectly to pass argv[] this way to function ?

Hi,

Please check the code segment.

/*************code start ****/

#include <stdio.h>
int func1(char **a_argv){
while (*a_argv!=NULL)
printf("\n%s", *a_argv++);
return(0);
}

int main(int argc, char *argv[]){
func1(&argv[0]);
}

/*************code end ****/

This func1 function prints all the arguments with no problem, because main() is probably always

on stack, so it works probably.

Do anyone see any problem, if one passes argv[] this way ? Will there be portability issues, like

on other UNIX flavors,etc.

Please let me know.

Thanks and Regards

Deepak

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