Greetings, The following should work:
#!/bin/sh sourcedir="/mount/windows/spaced name" cp "$sourcedir"/* $target On Monday 11 February 2002 20:22, Neal Lippman wrote: > Sorry for OT posting; I am not sure if there is a newsgroups for bash > experts, so I figured I'd try here. > > I need to be able to write a bash script that can copy files from a > directory who's name includes a space (long story, but it's a windows > directory under Win98 on a machine on my network). > > Anyway, supposing that the directory is "/mount/windows/spaced name" and I > need to copy all of the files in the directory to a target. > > At a bash prompt, I can issue either: > cp "/mount/windows/spaced name/*" target > OR > cp /mount/windows/spaced\ name/* target > and all works fine. > > However, from within a bash script, something like: > > #!/bin/sh > sourcedir=/mount/windows/spaced\ name > cp $sourcedir/* target > > fails, because the space isn't properly passed to cp, AND further the shell > doesn't do expansion on the wild card in the file name. > > I have tried all sorts of variants: > sourcedir="/mount/windows/spaced\ name" > sourcedir="/mount/windows/spaced\\ name" > sourcedir=/mount/windows/spaced\\ name" > > and the cp command with various quotes and not quotes, and cannot seem to > get this to work. Within the script, if I try: > > sourcedir="mount/windows/spaced\ name" > anotherdir="mount/windows" > echo $sourcedir/* > echo $anotherdir/* > > the first echo shows that there is no expansion of the wild card, while the > second echo works as expected, echoing the name of every file in > /mount/windows. > > Clearly the problem is that dreadful space in the directory name. Any help > on how to syntax this greatly appreciated. > > Thanks. > N
