on Tue, Jan 01, 2002 at 06:48:40PM -0800, Craig Dickson ([EMAIL PROTECTED]) wrote: > Jijo Jose A wrote: > > > I had a bash script and it have the line > > > > #--------- script begins > > cd /usr/share/doc > > pwd > > exit 0 > > #---------- ends > > > > when i run the code within HOME > > it outputs > > > > /usr/share/doc > > > > but after i exited from the script ,current directory remains the HOME. > > i need to cd through the script .what can i solve this ? > > Your script is executed in a subshell, so of course your main shell > isn't affected by the change of directory.
Yes. Understanding the issues involved in GNU/Linux shells, processes,
environments, and inheritance, is key.
What the original shell essentially does is:
I give birth to a child.
I tell the child to go down the street.
I tell the child to say were it is.
I kill my child (who says CompSci ain't brutal?).
I look where I am.
...surprise -- you're not in the place your child was. But you never
went there.
> You could simply source the script instead of executing it in a
> subshell, but I think a better solution would be to make this an
> alias.
I'd use a function. More flexible, essentially possible to do anything
you can do in a shell script. Though exiting is not generally
recommended:
$ function foo () { cd /usr/share/doc; pwd; }
$ foo
/usr/share/doc
$ pwd
/usr/share/doc
The function works on the current process. No birthing of children
involved (and less blood on your hands afterward).
Of course, there is a cost -- you're burdening your process with
remembering the function (it's stored in the processes environment).
$ typeset -f foo
foo ()
{
cd /usr/share/doc;
pwd
}
To free yourself:
$ unset foo
Peace.
--
Karsten M. Self <kmself@ix.netcom.com> http://kmself.home.netcom.com/
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