On Fri, Aug 31, 2001 at 08:07:01AM -0500, ktb wrote:
> On Thu, Aug 30, 2001 at 10:51:12PM -0700, Karsten M. Self wrote:
> > on Thu, Aug 30, 2001 at 11:09:07PM -0500, ktb ([EMAIL PROTECTED]) wrote:
> > > On Thu, Aug 30, 2001 at 08:45:29PM -0700, Vineet Kumar wrote:
> > > >
> > > > * Brian Schramm ([EMAIL PROTECTED]) [010830 19:41]:
> > > > > Is there a way that I can take a passwd file and compare the full
> > > > > name data
> > > > > in it to the email ldap server and give a a list of what it finds and
> > > > > what it
> > > > > misses? I am doing this manually but with the number of users that
> > > > > there are
> > > > > involved it is going to be really time consuming.
> > > >
> > > > I don't really know what I'm talking about, but this should probably
> > > > help you get started:
> > > >
> > > > awk -F : '{print $5}' /etc/passwd | sed -e "s/^\([^,]*\).*$/\1/"
> > > >
> > > > That will give you a list of just the full names. Pipe that into
> > > > something else that will look each one up in the directory service.
> > > >
> > > > Not a complete answer, but it's a start...
> > >
> > > BTW what does [ sed -e "s/^\([^,]*\).*$/\1/" ] accomplish? I'm just
> > > grooving on one liners lately and am curious. It seems like -
> > > awk -F : '{print $5}' /etc/passwd is all you need to spit out the full
> > > names.
> >
> > Not quite the same thing:
> >
> > $ awk -F : '/karsten/ {print $5}' /etc/passwd
> > Karsten M. Self,,,
> >
> >
> > $ awk -F : '{print $5}' /etc/passwd | sed -e "s/^\([^,]*\).*$/\1/"
> > Karsten M. Self
> >
> > In the original pattern:
> >
> > sed -e "s/^\([^,]*\).*$/\1/"
> >
> > We have:
> >
> > -e: expression to evaluate.
> > s: create a substitution using the following pattern.
> > / start of expression
> > ^ beginning of line (actually, beginning of fifth field
> > \( start a substitution
> > [^,]* match zero or more instances of any character other than ','
> > \) end substitution
> > .*$ match to end of line
> > / end of expression
> > \1 replace with contents of first substitution (the \([^,]*\)
> > pattern)
> > / end expression
> >
> > sed is for people who think Perl's too easy to understand.
Roflmao...
Cliff
