It is my understandng that in order for C++ to "delete" a dynamically-allocated
object, that object need to have been created via "new".
That said, I'd like to see the code where you do the allocation.
Also, you may need to type-cast the void pointer. The new compiler version
may be more picky about that sort of thing (though if that's the case it should
be a warning, not an error).
The comp.lang.c++ people will peobably be more helpful though.
If you do get a response, could you forward me a copy? thanks.
Bryan
On 15-Feb-2000 Shao Zhang wrote:
> Hi,
> I have posted this to comp.lang.c++, but hope someone here can
> help me as well. Thanks.
>
> =====================
> I have a c++ program that compiles fine with
> earlier version of g++, but it no longer compiles with
> the newsest release 2.95.2.
>
> Here is the relevant bit of code:
>
> typedef struct List
> {
> void **hd; /* first item */
> void **cr; /* current item */
> void **tl; /* last item */
> void **mx; /* max item before growing is
> required */
> int grow_size;
> } List;
>
> Some macros defined:
>
> #define fast_list_first(l) ((l && l->hd)? *(l->cr = l->hd) : 0)
> #define fast_list_last(l) ((l && l->hd)? *(l->cr = l->tl) : 0)
>
> And a Function like this:
> void lfree(List *l)
> {
> void *item;
> for (item=fast_list_first(l); item != NULL;
> item=fast_list_last(l))
>###->>>> delete item;
> }
>
>
> When compiled with g++(2.95.2), it failed with this:
> [line 55 is the line marked with arrows above]
> % g++ -g -c misc.c
> misc.c: In function `void lfree(List *)':
> misc.c:55: warning: `void *' is not a pointer-to-object type
>
> It gives me the warning message, but no .o file is created, and
> if I put it in a makefile, it results:
> % make misc.o
> g++ -g -c misc.c
> misc.c: In function `void lfree(List *)':
> misc.c:55: warning: `void *' is not a pointer-to-object type
> make: *** [misc.o] Error 1
>
>
> Thanks for any help in advance.
>
> Shao.
>
>
> --
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