In your email to me, Pete Templin, you wrote:
> 
> 
> Hi there,
> 
>       I'm in the process of setting up a 486 sx/25 as a dialup router
> (with one modem and one network card).  Unfortunately, the ISP can't seem
> to get the external routing right yet, so my testing is being held up.
> 
>       The question is this: I've compiled a lean, mean kernel with the
> appropriate IP forwarding enabled (no firewalling or masquerading is being
> used).  Will it "route" by default, or do I need to add a specific package
> or other external software?
> 
>       Here's the output of "route":
> 
> Kernel IP routing table
> Destination     Gateway  Genmask         Flags Metric Ref    Use Iface
> cs10.mil.ptd.ne *        255.255.255.255 UH    0      0        2 ppp0
> cs10.mil.ptd.ne *        255.255.255.255 UH    1      0        0 sl0
> 204.186.230.0   *        255.255.255.0   U     0      0       35 eth0
> 127.0.0.0       *        255.0.0.0       U     0      0       18 lo
> default         *        0.0.0.0         U     0      0       87 ppp0
> default         *        0.0.0.0         U     1      0       15 sl0    
> 
> The modem is 204.186.27.145 (cs10-01.mil.ptd.net).  Our IP addresses (not
> yet completely routed, but will be routed through the modem) are:
> 204.186.230.1, 204.186.230.2, 204.186.230.3 .  The first address is given
> to the network card in the Linux dialup router, and the second address is
> assigned to an NT server on the network, so once the external router to
> the ISP recognizes the route, pinging 204.186.230.2 is a good test.

I take it that the sl0 is a dialup connection? You have to add a static
route (maybe) and proxyarp it (arp -s). The rest should be OK. The dialups
are the real pains since they have no MAC address to arp to.

Tim

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** Disclaimer: My views/comments/beliefs, as strange as they are, are my own.**


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