On 5/8/05, Kamaraju Kusumanchi <[EMAIL PROTECTED]> wrote:
Hi Using Debian sid. I have an alias in my .bashrc say something like
alias x="y"
This command is executing fine on a bash shell (ie I can use x). But when I use x in a makefile, it is not getting expanded to y. Is this a future? How can I overcome this limitation?
Unless you've told it otherwise, make isn't using bash, it's using sh. While sh is probably a symlink to bash, when invoked as "sh" it doesn't read your .bashrc (nor the system default). You can change this behavior with the SHELL variable in your makefile:
SHELL := /bin/bash
Thanks. I will try that.
In general, though, it's better to set everything that you need in the makefile, since relying on your aliases makes your makefile highly non-portable. I usually do something like (using your example):
X := y
and then using $(X) instead of the alias x in commands.
Actually for me the reason for sourcing the .bashrc is for portability! This is my situation. Consider two machines A and B. I use gfortran compiler on these machines with the same makefile. I have latest gcc-snapshot on machine A and a bit older gcc-snapshot on machine B. The latest gcc-snapshot package names the gfortran executable as gfortran-20050507-1 while the older gcc-snapshot calls it gfortran. This makes the makefile non-portable (as it relies on compiler set to gfortran) across A and B. So I decided to put an alias for gfortran in the .bashrc of machine A, so that gfortran will in turn call gfortran-20050507-1. Is there any other portable solution way for this situation?
Thanks for the reply again. raju
--
To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
