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and subject line Bug#261513: My fault, implicit declaration with overflow
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From: MASSONIE Dominique <[EMAIL PROTECTED]>
To: Debian Bug Tracking System <[EMAIL PROTECTED]>
Subject: gcc-3.3: strtof only in c99 but not undefined reference otherwise
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Package: gcc-3.3
Version: 1:3.3.4-5
Severity: normal
-- System Information:
Debian Release: testing/unstable
APT prefers unstable
APT policy: (500, 'unstable')
Architecture: i386 (i686)
Kernel: Linux 2.4.24+d1
Locale: LANG=C, LC_CTYPE=C
Versions of packages gcc-3.3 depends on:
ii binutils 2.14.90.0.7-8 The GNU assembler, linker and bina
ii cpp-3.3 1:3.3.4-5 The GNU C preprocessor
ii gcc-3.3-base 1:3.3.4-5 The GNU Compiler Collection (base
ii libc6 2.3.2.ds1-13 GNU C Library: Shared libraries an
ii libgcc1 1:3.4.1-3 GCC support library
-- no debconf information
/*
The following sample code uses function "strtof".
Compiled without -std=c99 it produces some bad results instead of a
compilation error (IMHO: undefined reference to `strtof')
*/
#include <stdlib.h> /* needed for strtod and strtof */
#include <stdio.h> /* needed for fprintf */
// some related information:
// - man strtod, strtof, strtold:
// CONFORMING TO
// ANSI C describes strtod, C99 describes the other two functions.
//
// - in /usr/include/stdlib.h
//
// #ifdef __USE_ISOC99
// __BEGIN_NAMESPACE_C99
// ...
// extern float strtof (__const char *__restrict __nptr,
// char **__restrict __endptr) __THROW;
// ...
// __END_NAMESPACE_C99
// #endif
int main (void)
{
const char buf[] = "123.45";
fprintf (stdout, "result %f == %f and 6 == %d\n",
(float)strtod (buf, NULL),
strtof (buf, NULL),
6);
exit (0);
}
// ok with: gcc -Wall -std=c99 test_strtof.c
//
// without -std=c99 should get (IMHO):
//: undefined reference to `strtof'
// but instead get broken output like:
// result 123.449997 == 0.000000 and 6 == 1073970383
---------------------------------------
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From: Matthias Klose <[EMAIL PROTECTED]>
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Date: Sat, 7 Aug 2004 09:01:02 +0200
To: MASSONIE Dominique <[EMAIL PROTECTED]>,
[EMAIL PROTECTED]
Subject: Re: Bug#261513: My fault, implicit declaration with overflow
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MASSONIE Dominique writes:
> Hi,
>
> I investigated a bit more my problem and found that what I expected about
> fprintf and the '6' was normal behavior (ie. %f waits for a double and
> strtof implicit declaration returns an int thus the 6 is lost in the call
> stack,
> as the warning shows).
>
> All is 'fixed' by simply changing the sample code with:
> int main (void)
> {
> const char buf[] = "123.45";
> const float f1 = (float)strtod (buf, NULL);
> const float f2 = (float)strtof (buf, NULL);
>
> fprintf (stdout, "result %f == %f and 6 == %d\n",
> f1,
> f2,
> 6);
> exit (0);
> }
>
> The missing or implicit declaration remains but that's ok.
> Thanks for closing this bigreport, sorry for the work.
done.
