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From: Ron Steinke <[EMAIL PROTECTED]>
To: Debian Bug Tracking System <[EMAIL PROTECTED]>
Subject: libstdc++5-dev: data_type typedef not recognized for std::map
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Date: Sat, 20 Sep 2003 19:55:07 -0700
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Package: libstdc++5-dev
Version: 1:3.2.3-8
Severity: normal
The following test code:
#include <map>
typedef std::map<int,int> MapType;
int main()
{
MapType::key_type foo = 0;
MapType::data_type bar = 0;
return bar;
}
fails with an error at the MapType::data_type line:
map_data_type_bug.cpp: In function `int main()':
map_data_type_bug.cpp:8: error: `data_type' is not a member of type `
std::map<int, int, std::less<int>, std::allocator<std::pair<const int, int>
> >'
map_data_type_bug.cpp:8: error: syntax error before `=' token
map_data_type_bug.cpp:10: error: `bar' undeclared (first use this function)
map_data_type_bug.cpp:10: error: (Each undeclared identifier is reported only
once for each function it appears in.)
key_type and value_type are recognized, but data_type is not. This breaks
conformance with the STL standard (and, of course, my code :)).
-- System Information:
Debian Release: testing/unstable
Architecture: i386
Kernel: Linux ouroboros 2.4.20 #5 Mon Apr 14 17:15:56 PDT 2003 i686
Locale: LANG=C, LC_CTYPE=C
Versions of packages libstdc++5-dev depends on:
ii g++-3.2 1:3.2.3-8 The GNU C++ compiler
ii gcc-3.2-base 1:3.2.3-8 The GNU Compiler Collection (base
ii libc6-dev 2.3.2-7 GNU C Library: Development Librari
ii libstdc++5 1:3.3.1-0pre0 The GNU Standard C++ Library v3
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Sun, 21 Sep 2003 00:13:44 -0400
Date: Sun, 21 Sep 2003 00:13:44 -0400
From: Phil Edwards <[EMAIL PROTECTED]>
To: Ron Steinke <[EMAIL PROTECTED]>, [EMAIL PROTECTED]
Subject: Re: Bug#211898: libstdc++5-dev: data_type typedef not recognized for
std::map
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On Sat, Sep 20, 2003 at 07:55:07PM -0700, Ron Steinke wrote:
>
> The following test code:
is broken.
> key_type and value_type are recognized, but data_type is not. This breaks
> conformance with the STL standard (and, of course, my code :)).
There is no "STL standard". The ISO C++ Standard defines no such typedef
as data_type; see clause 23.
--
Debugging is twice as hard as writing the code in the first place.
Therefore, if you write the code as cleverly as possible, you are,
by definition, not smart enough to debug it.
- Brian W. Kernighan
