The following code does not compile with g++-3.0 and g++-3.1, but it does with g++-2.95.4. What is wrong (std:: is not missing!)?
Oh, std:: was missing - in a way ...
std::find only looks in namespace std:: for an operator==, if I specify it inside namespace std { ... } , it works.
Gives me a strange feeling though to declare user supplied operators in std.
Perhaps the namepace of the first argument determines the namespace searched for the operator ?
Christof
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