On 1 Oct 1999, Ben Pfaff wrote:
> Dale Scheetz <[EMAIL PROTECTED]> writes:
>
> > $ grep -w debhelper override.potato
> > debhelper optional devel
> > hello-debhelper optional devel
> >
> > In the man page, under the -w option, it says that, in order to match, the
> > string must be either at the beginning of the line, or preceeded by a
> > non-word contituent character, which it declares as letters, digits, and
> > the underscore.
>
> No, it says that those are word constituent characters.
That's what I meant...
>
> > The hyphon at the ned of hello in "hello-debhelper" isn't any of these,
> > but grep declares it to match anyway! Is this something to do with the
> > form of my expression?
>
> It's preceded by a character that isn't a letter, digit or underscore:
> a hyphen.
>
Which confused me as to why it was being included in the "word".
So a "search string" is defined as any characters delimited by blank, tab,
or newline, but because the hyphon is not considered a "word constituent"
character, debhelper is considered a "whole word" within the string
"hello-debhelper"?
While this seems to be working with two definitions of what is a word (the
parser considers hello-debhelper as "one word" while the expression
analysis considers it two words), I can accept that this is the true state
of affairs.
This leaves me with the unresolved problem of distinguishing between the
two package names.
I just read through the grep manpage (again) looking for something that
will enforce an exact match, when I realised that I can simply skip this
step and do the selection in awk (which I was using before to peel off the
section name from the grep output), so the right command is:
awk -v name=debhelper ' name == $1 { print $3 } ' override.potato
which produced the single line:
devel
rather than:
grep -w debhelper override.potato |awk '{ print $3 }'
which produced the two line ouput:
devel
devel
Thanks for the education, problem-set can be a real killer.
Luck,
Dwarf
--
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