Sergei Golovan wrote:
int status = fork();
if (status != 0)
return 0;
status = fork();
if (status != 0)
return 0;
Apart from what everyone else has said, I can't help put being slightly
puzzled that it calls fork two times. This just seems weird...
Or did I miss something? Brian May -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]

