On 11/12/2011 04:09 AM, Regid Ichira wrote:
$ sed -i '$w/dev/stdout;$d' testFile
sed: couldn't open file /dev/stdout;$d: Permission denied
Oops, sorry:
sed -i -e '$w/dev/stdout' -e '$d' testFile
Regardless, I am not sure whether one, who is fluent in the sed
language, should be able to predict the outcome of sed -i '$p'. I mean,
where it is defined in which line would the content of the output will
appear in the file?
sed operates strictly line-by-line. It reads "1", doesn't execute "$p"
and terminates the cycle by printing "1". It reads "2", executes "$p"
since it's the last line, and terminates the cycle by printing "2".
? In case you claim that with -i, the seek position of the input
and output files are expected to point to the same location,
subjected to possible previous operations in the script or script-file:
Was I supposed to deduce that from the manual?
Yes. -i does not change the operation of sed in any way, it just
provides a shorthand for replacing the original file with a modified copy.
Paolo
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