> > +# Install localization-config only if "LANG"" != en_US or
> > +# arch is powerpc.
> > +# LANG is NOT defined here so we use LANGUAGE AND COUNTRY
> > +# This is made here because we also need the country choice
> > +if [ "$LANGUAGE" != "C" ] ; then
> > + if [ "$LANGUAGE" != "en" -o "$COUNTRYCODE" != "US" ]; then
> > + pkginstall localization-config
> > + else
> > + if [ "$ARCH" = "powerpc" ]; then
> > + pkginstall localization-config
> > + fi
> > + fi
> > +fi
>
> The previous test checks whether $LOCALE is not equal to C. Could
> your new clause be simplified to
>
> if [ "$LOCALE" != C -a \( "$LOCALE" != en_US -o "$ARCH" = powerpc \) ]; then
> pkginstall localization-config
> fi
Barely, yes. I have to admit that I was missing the exact appropriate
syntax for conditional grouping in test...especially escaping the
parentheses...
However, the test should IMHO not be on LOCALE for en_US because in
that case LOCALE could be en_US.UTF-8 or en_US.ISO-8859-1 as well as
en_US alone and we probably don't want l-c to be installed there as
well. So, the test becomes:
if [ "$LOCALE" != C -a \
\( \
\( "$LANGUAGE" != en -o "$COUNTRYCODE" != US \) \
-o "$ARCH" = powerpc \
\) \
]; then
(not sure whether my indenting is correct)
This resumes to:
"if LOCALE is not C AND ((LANGUAGE not en or COUNTRY not US) or ARCH not ppc)"
