Quoting from "Shell & Utilities"/"2.6.4 Arithmetic Expansion" of SuSv3:
"If the shell variable x contains a value that forms a valid integer constant, then the arithmetic expansions "$((x))" and "$(($x))" shall return the same value." I cannot seem to find any reasonable way to parse this other than that $((x+1)) should be treated in the same way that $(($x+1)) would be. Regards: David Weinehall -- /) David Weinehall <[EMAIL PROTECTED]> /) Rime on my window (\ // ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ // Diamond-white roses of fire // \) http://www.acc.umu.se/~tao/ (/ Beautiful hoar-frost (/ -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
