On Tue, Oct 01, 2024 at 12:45:13AM +0200, Thorsten Glaser wrote:
> Package: popularity-contest
> Version: 1.76
> Severity: normal
> X-Debbugs-Cc: t...@mirbsd.de
>
> -rw-r--r-- 1 root root 21239 Sep 26 11:06 popularity-contest
> -rw-r--r-- 1 root root 21260 Sep 26 06:25 popularity-contest.0
> -rw-r--r-- 1 root root 4875 Sep 19 11:06 popularity-contest.1.gz
> -rw-r--r-- 1 root root 4883 Sep 19 06:25 popularity-contest.2.gz
> -rw-r--r-- 1 root root 4864 Sep 12 11:06 popularity-contest.3.gz
> -rw-r--r-- 1 root root 4893 Sep 12 06:25 popularity-contest.4.gz
> -rw-r--r-- 1 root root 4878 Sep 5 11:06 popularity-contest.5.gz
> -rw-r--r-- 1 root root 4871 Sep 5 06:25 popularity-contest.6.gz
This is more or less intended...
There are two cron jobs, one weekly and one daily.
The weekly run predictably when the sysadmin has configured daily cronjob
to run (6:25 by default).
The daily run actually at a random time of the week.
Normally if the daily succeed, then the weekly is skipped, but there
is a tolerance if the daily is more than 6.5 days old, then the
weekly is run anyway, so yes it will run twice in that case.
You can check the detail in /etc/cron.daily/popularity-contest:
if [ "$MODE" != "--crond" ] || ( [ "$DAY" ] && [ "$DAY" != "$(date +%w)" ] ) ;
then
# Ensure that popcon runs at least once in the last week
if [ -f "$POPCONOLD" ] ; then
now=$(date +%s)
lastrun=$(last_sub)
if [ "$MODE" = "--crond" ]; then
# 7.5 days, in seconds
week=648000
else
# 6.5 days, in seconds
week=561600
fi
if [ "$(( $now - $lastrun ))" -le "$week" ]; then
exit 0
fi
fi
fi
Cheers,
Bill
