Hi, Quoting Helmut Grohne (2024-09-30 22:08:04) > It is not clear to me whether marking it Multi-Arch: foreign would be correct > and seek input from others (hello d-cross@l.d.o).
I had some contact with bpftool via the src:linux packaging, so I tried finding out the correct answer to this question and the answer seems to be: BPF is mostly architecture independent *except* that it uses the endian-ness of its own architecture for the content it writes. This is what is also documented here: https://docs.kernel.org/bpf/standardization/instruction-set.html And this property was confirmed by Ben Hutchings in #debian-kernel. Since big endian architectures still exist, I don't think we need to research further and can confidently declare that no, bpftool cannot be M-A:foreign. Thanks! cheers, josch
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