Paul J. Lucas wrote:
Here's a small test program:#include <fcntl.h> #include <cstdlib> #include <iostream> using namespace std; int main() { int fd = ::open( "ESLF", O_RDONLY ); if ( fd == -1 ) { cerr << "could not open ESLF file" << endl; ::exit( 1 ); } char buf[ 64 ]; ssize_t bytesRead = ::read( fd, buf, sizeof( buf ) ); cout << "read " << bytesRead << " bytes" << endl; ::close( fd ); } Here's the contents of a small biinary file "ESLF" (printed in hex bytes): 54 39 CA 1A 44 When I compile the program as: g++ -o test test.cpp and run it, it prints "read 5 bytes" as one would expect. When I compile the program as: g++ -mno-cygwin -o test test.cpp and run it, it prints "read 3 bytes". Why? How do I teg it to read all 5 bytes?
Ask the MinGW llist, since -mno-cygwin simply enables you to run their compiler "indirectly". As a result, questions about the MinGW compiler are off-topic for this list, since it's not Cygwin. See <http://mingw.org/>. -- Larry Hall http://www.rfk.com RFK Partners, Inc. (508) 893-9779 - RFK Office 838 Washington Street (508) 893-9889 - FAX Holliston, MA 01746 -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
