On Nov 9 14:41, cyg Simple wrote:
> On 11/9/2016 1:13 PM, cyg Simple wrote:
> > The following program demonstrates the issue. Should issetugid be
> > declared with this scenario?
> >
> > /*****************************************************/
> > #define _XOPEN_SOURCE 1 /* Causes declare warning */
> > #define __BSD_VISIBLE 1
> > #include <unistd.h>
> >
> > int main(int argc, char ** argv) {
> > int result;
> > result = issetugid();
> > }
> > /****************************************************/
> >
>
> Because when _XOPEN_SOURCE is 1 _DEFAULT_SOURCE doesn't get set which
> then #undef __BSD_VISIBLE and and sets it to 0. See
> /usr/include/sys/features.h.
>
> If I #define _DEFAULT_SOURCE 1 before the #include then the above code
> works. However, should it?Yes. You have a bug in your code. Never (and I mean *never*) use the __foo_VISIBLE macros in your code. Please read the long comment preceeding the visibility macro handling in /usr/include/sys/features.h. You want to use either _DEFAULT_SOURCE or _BSD_SOURCE (deprecated but probably available for another 100 years). Also, note the description of the __foo_VISIBLE macros later in the file. It introduces the macros as "private" macros. HTH, Corinna -- Corinna Vinschen Please, send mails regarding Cygwin to Cygwin Maintainer cygwin AT cygwin DOT com Red Hat
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