On Sun, Jan 13, 2013 at 7:55 PM, YZFury <yzf...@gmail.com> wrote:
> int *ptr = malloc(sizeof(*ptr));
> int x = 87;
> ptr = &x;
> printf("%d", *ptr);
> free(ptr);//it goes wrong here
As you probably know, you can't call free() on a pointer
that didn't come from malloc(). ptr's first value came from malloc,
but you overwrote that with
ptr = &x;
Perhaps you meant
*ptr = x;
So you're a level of indirection off.
- Dan
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