>>> I checked the Make file, it used this flag: >>> gcc -mno-cygwin -g -Wl,--add-stdcall-alias -Wl,--export-all-symbols ... >> >> replace gcc by gcc-3 >> gcc 4 is now the default on cygwin but the cross compiler is not >> supported for that version. >> Frédéric > > What do you mean by not supported? JonY maintains the cross compilers....
I meant that i686-w64-mingw32-gcc exists but not i686-w32-mingw32-gcc. I thought that w64 meant "built on win64" and mingw32 "run binary on win32". So it seems to me that with cygwin running on a 32 bit windows, it is not possible to cross compile to win32. However with a 64 bit windows you can produce win32 applications. However, I just tried to use i686-w64-mingw32-g++ on my win32 machine with a hello world program and it produces an binary that can be used from windows on that win32 machine. So my question to the list: what is the meaning of w64 in the name? Frédéric -- Problem reports: http://cygwin.com/problems.html FAQ: http://cygwin.com/faq/ Documentation: http://cygwin.com/docs.html Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple
