From Thu, 23 Aug 2007 08:27:48 +0200 Gerhard Kulzer <[EMAIL PROTECTED]> wrote:
> I have a seemingly stupid question: If we settled for the 5th order > model but used the 4th order data until our DB would fill up, then we > also can used the fast 3rd order preview mode? Since the 3rd order is > available in both models. The fast algorithm can be implemented only for the rd = k1 * ru^5 + k2 * ru^3 model; a particular case is when k1 == 0 so you have just k2 * ru^3. However I don't quite get it how you're going to get the 3rd or 5th order "fast" model from 4th order data... Keep in mind that this is an incomplete 5rd order polynom, e.g. fast implementation is possible only if in the equation below c4 == c2 == 0: rd = c5 * ru^5 + c4 * ru^4 + c3 * ru^3 + c2 * ru^2 + c1 * ru -- Andrew
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