Hello Magik,
. [2019-01-09 21:51 +0100]:
> I'm C programmer learning now Cockpit. My problem is as follows: for some
> of the operation I must use external helper and I must wait for it output.
> The cockpit.spawn() function returns the promise, which is non-blocking
> operation (as expected). How can I make it work as blocking one? Which
> mean: the rest of the code in the function should be done after receiving
> full output of the cockpit.spawn (done() or fail())
This is a common pitfal when coming from the world of synchronous programming
languages (such as C or Python) and starting with asynchronous JavaScript.
Daniel's await proposal can certainly help to make async code look like it was
written in a sync style; but honestly, it's really best to let go of this
pattern when writing JS.
So instead of
output = cockpit.spawn(..).make_this_magically_sync();
followup_action(output);
actually use JavaScript promises as they are intended:
cockpit.spawn(..)
.then(output => {
followup_action(output);
})
.catch(err => {
console.error(err);
});
i. e. organize the stuff that depends on the result into promise handlers.
Martin
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