529:[mjack...@ferb:x64]$ export CXXFLAGS="-arch x86_64"
530:[mjack...@ferb:x64]$ rm -rf *; cmake ../
-- The C compiler identification is GNU
-- The CXX compiler identification is GNU
-- Check for working C compiler: /usr/bin/gcc
-- Check for working C compiler: /usr/bin/gcc -- works
-- Detecting C compiler ABI info
-- Detecting C compiler ABI info - done
-- Check for working CXX compiler: /usr/bin/c++
-- Check for working CXX compiler: /usr/bin/c++ -- works
-- Detecting CXX compiler ABI info
-- Detecting CXX compiler ABI info - done
-- CMAKE_SIZEOF_VOID_P: 8
-- Configuring done
-- Generating done
-- Build files have been written to: /Users/mjackson/Desktop/Test/x64
For those reading this after the fact or from a google search...
So. where does this leave us? Basically if you ONLY do one arch or
another on OS X using this type of technique is probably fine. If you
are building Universal binaries then some thing more in-depth would be
needed if the explicit detection of the size of a void pointer is
needed. Probably something using the standard apple #ifdef __APPLE__
&& __LP64 or something like that.
This may still fall apart if someone wrote a program to spit out
various stats on the system, the executable was built as a universal
binary, ran as a 32 bit executable but the user was expecting a 64 bit
executable to be run. Maybe none of this matters.
At least I figured out that much today. ;-)
mike
On Jun 11, 2009, at 3:37 PM, Bill Hoffman wrote:
Michael Jackson wrote:
So it builds a 32 bit executable.
:)
Are you saying (from above) that if I have a 64 bit build of CMake
then I will get 64 bit binaries by default?
No, it depends on the flags given to the compiler. I think you want
-m64. So if you do this:
export CFLAGS=-m64
mkdir Build64
cd Build64
cmake ../Test
make
Then you will get a 64 bit build.
-Bill
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