One option is to use keep-indexed:
(first
(keep-indexed
(fn [i xs]
(first
(keep-indexed
(fn [j x]
(when (= x "5")
[i j]))
xs)))
players))
On Wednesday, December 7, 2016 at 5:32:10 PM UTC+1, Rickesh Bedia wrote:
>
> If I have
>
> (def players [["1" "2" "3"] ["4" "5" "6"] ["7" "8" "9"]])
>
> How would I get the index of number 5? I think it should be [1 1] but
> don't know how to get this
>
> If it were more simple such as
>
> (def players ["1" "2" "3"])
>
> I can get the index using
>
> (.indexOf players "2") > 1
> (.indexOf players "3") > 2
>
>
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