These two forms are equivalent:
(__ (sort (rest (reverse [2 5 4 1 3 6]))))
(-> [2 5 4 1 3 6] (reverse) (rest) (sort) (__))
The -> macro turns the second form into the first. You can see this by
running macroexpand-all:
(require '[clojure.walk :refer [macroexpand-all]])
(macroexpand-all '(-> [2 5 4 1 3 6] (reverse) (rest) (sort) (__)))
This should produce:
(__ (sort (rest (reverse [2 5 4 1 3 6]))))
- James
On 30 April 2014 16:28, Roelof Wobben <[email protected]> wrote:
> On 4 clojure there it this exercise:
>
> (= (__ (sort (rest (reverse [2 5 4 1 3 6]))))
> (-> [2 5 4 1 3 6] (reverse) (rest) (sort) (__))
> 5)
>
> if I understand it right this is happen
>
> reverse[ 2 5 4 1 3 6] gives [ 6 3 1 4 5 2 ]
> Then rest [ 6 3 1 4 5 2] gives [ 3 1 4 5 2]
> Sort this and you get [ 1 2 3 4 5]
>
> This part : [2 5 4 1 3 6] (reverse) (rest) (sort) gives the same output: [
> 1 2 3 4 5]
>
> what does the (__)) 5) does exactly. When I change the 5 to another number
> the outcome is not changed.
> And where does clojure put the first [ 1 2 3 4 5 ] in the second form ?
>
> Roelof
>
>
>
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