Following up on this. Is the following correct:
* async/thread creates Java threads -- these _are_ root gc objects
* async/go creates go "blocks", which in reality, is just a state
machine. go-blocks are NOT root gc objects
* go-blocks do _NOT_ have stackframes -- they're just a simple, flat
state machine created via inversion of control at <!, >!, and alt!
locations
* when a go-block blocks, it gets appended to either the put or the
take queue of the channel it's blocking on
Thus, in the following code:
(let [c (async/chan)
d (async/go (<! c))] )
what happens is the following thing:
* we create a channel "c"
* we create a go-block, who returns to a channel "d"
* the go block hits (<! c), then gets ioc-ed into a state machine
* this state machine is put on the "take-list" of "c"
Then, the GC collects "c" and "d" -- and the go-block vanishes, since
it's just a state machine attached to "c"
Can you please tell me if
(1) all above statements are correct or
(2) correct the wrong ones in place?
Thanks!
On Thu, Jan 30, 2014 at 11:06 AM, t x <[email protected]> wrote:
>> The key thing to remember in all questions of core.async GC is that there is
>> no global "blocked gos" queue. Instead, the blocked "gos" are attached
>> directly to the channel. When the channel is GC'd all attached gos are GC'd
>> as well.
>
> This is the source of all my mis-understanding. Thanks for explaining!
>
>
>>
>> So in this case, it's actually even simpler.....the go never blocks. What
>> this code is doing is creating a channel to return from the go. This channel
>> has a buffer size of 1. It then puts a channel into the channel. The go then
>> exits and is GC'd. Once the return channel is discarded by the caller of
>> this code, both channels are also GC'd
>>
>> Timothy
>>
>>
>> On Thu, Jan 30, 2014 at 11:24 AM, t x <[email protected]> wrote:
>>>
>>> Hi,
>>>
>>> Consider this block of code:
>>>
>>> (async/go (async/chan))
>>>
>>> This creates a go-thread and a go-chan.
>>>
>>> The go-thread is linked from the list of blocked go-threads.
>>>
>>> The go-chan is linked from the go-thread.
>>>
>>> Thus, did we just create a go-thread and a go-chan which is NOT gc-ed at
>>> all?
>>>
>>> Thanks!
>>>
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>>
>>
>>
>>
>> --
>> "One of the main causes of the fall of the Roman Empire was that-lacking
>> zero-they had no way to indicate successful termination of their C
>> programs."
>> (Robert Firth)
>>
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