Sorry, I spoke without seeing that you were aware of partition-by. Here's
one that isn't vectorized.
(def v ["foo" 1 "bar" 10 20 "clown" 5])
(->> v
(partition-by string?)
(partition 2)
(map #(apply concat %)))
On Sunday, December 1, 2013 2:10:04 PM UTC-5, Ben wrote:
>
> user=> (def v ["foo" 1 "bar" 2 3 "baz" 4])
> #'user/v
> user=> (first (reduce (fn [[res s] e] (if (string? e) [res e] [(conj res
> [s e]) s])) [[] nil] v))
> [["foo" 1] ["bar" 2] ["bar" 3] ["baz" 4]]
>
> On Sun, Dec 1, 2013 at 10:57 AM, Ryan <[email protected] <javascript:>>wrote:
>
>> Hi all,
>>
>> I have a vector which contains an unknown number of repetitions of the
>> following pattern:
>>
>> String, followed by 1 or more integers
>>
>> For example:
>>
>> String
>> Integer
>> String
>> Integer
>> Integer
>> String
>> Integer
>> Integer
>> Integer
>> String
>> Integer
>>
>> What I am trying to do is to create a vector of pairs which each pair
>> will be the string and the integers followed.
>>
>> Real example:
>>
>> foo
>> 1
>> bar
>> 10
>> 20
>> clown
>> 5
>>
>> should convert to:
>>
>> [[foo 1] [bar 10] [bar 20] [clown 5]]
>>
>> I did try to play around with partition-by, partition and instance? but I
>> couldn't get it quite right.
>>
>> Thank you for your time
>>
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>
>
>
> --
> Ben Wolfson
> "Human kind has used its intelligence to vary the flavour of drinks, which
> may be sweet, aromatic, fermented or spirit-based. ... Family and social
> life also offer numerous other occasions to consume drinks for pleasure."
> [Larousse, "Drink" entry]
>
>
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