Hi,
AFAIK the currently supposed way of parsing XML with Clojure is to use a
combination of clojure.xml, clojure.zip, data.zip and data.zip.xml. Please
correct me if I'm wrong.
I am trying to extract the equivalent of a union of nodesets from an XML
file (speaking in XPath terms).
Example:
input.xml:
<root>
<a>
<b1>
<c>C1</c>
<c>C2</c>
</b1>
<b2>
<c>C3</c>
<c>C4</c>
</b2>
<b3>
<c>C5</c>
<c>C6</c>
</b3>
</a>
</root>
Suppose I have an array (or whatever) with the allowed b-tags, e.g. b1 and
b3. Now I want to extract all c-tags underneath b1 and b3 but skip those
under b2.
Using clojure.xml/parse, clojure.zip/xml-zip and data.zip.xml/xml-> I can
easily extract certain nodes but I have not found a way to extract such a
union, yet.
A rather lispy approach would be using or in a manner similar to this:
(def x (clojure.zip/xml-zip (clojure.xml/parse "/path/to/input.xml")))
(clojure.data.zip.xml/xml-> x :a (or :b1 :b3) :c)
And I did not yet understand how to write my own predicates there.
Any pointers?
Kind regards,
stefan
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