On 16 May 2012 19:18, Jim - FooBar(); <[email protected]> wrote:
> But it is already a double array, or at least it should be because that is
> what normalize returns...Why start copying into a new array?

Oh ok, so that's what data is. I got confused.

Anyway -- does the function displayed in function.png work if you just
type it in at the REPL (wrapped in a (let [data some-array-of-doubles]
...), I guess)?

M.

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