all function arguments will be evaluated .... so, 123 was printed

On Thu, May 3, 2012 at 4:06 AM, thomas <[email protected]> wrote:

> the arguments to randomly-fn are evaluated before the macro-expansion of
> randomly kicks in.
> (that's what macros are for: control if, where and how often an expression
> is evaluated)
> So why would you need randomly-fn anyway?
> You can just write
>
> randomly (print 1) (print 2) (print 3))
>
> and this works.
>
>
> Am 02.05.2012 um 16:09 schrieb 金山:
>
> > I defined a macro like this:
> > (defmacro randomly [& exprs]
> >  (let [len (count exprs)
> >        ind (rand-int len)
> >        conditions (map #(list '= ind %) (range len))]
> >    `(cond ~@(interleave conditions exprs))))
> >
> > and then defined a function :
> > (defn randomly-fn [& exprs]
> >     (randomly exprs))
> >
> > I think there may be a mistake because of the randomly-fn didn't work
> > as expected.
> >
> > (randomly-fn (print 1) (print 2) (print 3))
> >
> > expected:
> > 1 or 2 or 3.
> > but returned:
> > 123
> >
> > where is the mistake?
> >
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