if (n == 0) return the "factorial", else go to the "loop label" and recur
with the two parameters (n--) and (factorial * n). Go on until n-- reaches
0.
In a Java-like translation we could have:
int n = number;
factorial = 1;
while(n > 0){
factorial *= n--;
}
return factorial;
On Sun, Apr 15, 2012 at 5:37 PM, Anto <[email protected]> wrote:
> Can anyone explain me what does the last three lines
> does:
>
> (loop [n number factorial 1]
> (if (zero? n)
> factorial (recur (dec n) (* factorial n))))
>
> Thanks in advance.
>
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