Not sure what kind of input you can get, but apply-ing list only on strings
would decompose them, so your function can be written as:
(defn ls [x]
(cond
(string? x)
(apply list (list x))
:else
(apply list x))))
as '(apply list nil)' will yield '().
Or, you can write it more lispy:
(defn ls [x]
(apply list (if (string? x)
(list x)
x)))
On Thursday, March 8, 2012 7:28:12 PM UTC+1, Brandon Harvey wrote:
>
> Hi,
>
> I'm seeking a small & idiomatic function that will take input and ensure
> it's wrapped in a list. If nil, I'd like the list to be empty. If the
> input is already a list, I don't want to wrap it in another list layer. So:
>
> "hi" => ("hi")
> nil => ()
> ("hi") => ("hi")
>
> (list '("hi")) => (("hi")) ; bad
> (apply list "hi") => (\h \i) ; bad
>
> So I've ended up writing the function with a conditional, like so. Is
> there a tidier way?
>
> (defn ls [x] (cond (list? x) (apply list x)
> (nil? x) '()
> :else (list x)))
>
>
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