A similar version:
(defn combinations [[x & xs]]
(if xs
(for [e x c (combinations xs)]
(cons e c))
(map list x)))
Juan Manuel
El lunes 27 de febrero de 2012 15:23:30 UTC+1, Bill Caputo escribió:
>
> Here's a version that uses destructuring (but is otherwise the same) that
> cleans it up a bit:
> (defn combinations [[x & xs]]
> (if xs
> (for [frstitems x tlitm (combinations xs)]
> (flatten (list frstitems tlitm)))
> x))
>
> On Feb 26, 2012, at 9:45 PM, Mike Ledoux wrote:
>
> > (defn combinations [items]
> > (if (== (count items) 1)
> > (flatten items)
> > (for [frstitems (flatten (first items))
> > tlitm (combinations (rest items))]
> > (flatten (list frstitems tlitm)))))
>
>
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