this seems easier...
user=> (map str "abc")
("a" "b" "c")
Though the original question says a list to a string and the example shows a
string to a list (of symbols)
user=> (apply str ["a" "b" "c"])
"abc'
But, the example is looks like it wants
user=> (map (comp symbol str) "abc")
(a b c)
Hopefully one of those is what you're looking for.
Cheers, Jay
On Jan 14, 2012, at 1:01 PM, dennis zhuang wrote:
> You can do this
> > ((comp #(map str %) seq) "abcdef")
> ("a" "b" "c" "d" "e" "f")
>
> 2012/1/15 Bruce Durling <[email protected]>
> Sam,
>
> Strings can be turned into sequences with seq.
>
> > (seq "foo")
> (\f \o \o)
>
> The backslashes are because f o and o are character literals.
>
> cheers,
> Bruce
>
> On Sat, Jan 14, 2012 at 10:13, Samuel Lê <[email protected]> wrote:
> > Hi,
> >
> > I was wondering if there was a function to convert a list into a string,
> > something like:
> > (string-to-list "abcde") ;; (a b c d e)
> >
> > thanks!
> >
> > Sam
> >
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