On Nov 9, 2:47 pm, Shoeb Bhinderwala <[email protected]>
wrote:
> (["a"] ["a" "b"] ["a" "b" "c"] ["a" "b" "c" "d"])
It should be pointed out that this result -- while it may be what you
actually want -- is not "all subsets of" ["a" "b" "c" "d"]. For that
you might want to use combinatorics/subsets:
user=> (C/subsets ["a" "b" "c" "d"])
(() ("a") ("b") ("c") ("d") ("a" "b") ("a" "c") ("a" "d") ("b" "c")
("b" "d") ("c" "d") ("a" "b" "c") ("a" "b" "d") ("a" "c" "d") ("b" "c"
"d") ("a" "b" "c" "d"))
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