How about this one?
(defn calc [total-values daily-values]
(map-indexed
(fn [i daily]
(* daily
(reduce #(* %1 (inc (/ %2 100.0))) 1.0 (nthnext total-
values (inc i)))))
daily-values))
Happy coding.
-huahai
On Jun 28, 10:11 pm, Justin Kramer <[email protected]> wrote:
> Here's one way.
>
> (defn tails [coll]
> (take-while seq (iterate rest coll)))
>
> (defn calc [total-values daily-values]
> (map * daily-values (for [tail (tails total-values)]
> (reduce #(* %1 (inc (/ %2 100.0)))
> 1.0
> (rest tail)))))
>
> In translating it, I first tried to visualize the algorithm[1]. Then I
> transcribed that visualization into the usual suspects: map/for,
> reduce, filter. Having a solid grasp of each of those -- not to
> mention the rest of clojure.core -- is very helpful.
>
> [1]http://i.imgur.com/XDZhm.png(crude drawing of the first step)
>
> Hope that helps,
>
> Justin
>
> On Jun 28, 8:20 pm, "Bhinderwala, Shoeb"
>
> <[email protected]> wrote:
> > Hi
>
> > I have been learning clojure for some time but am a bit stumped when
> > translating code with nested for loops.
>
> > Can someone help me to translate the following java code to clojure
> > elegantly:
>
> > The inputs are two arrays of type double of the same length -
> > dailyValues and totalValues. The output is the array contrib of the same
> > length.
>
> > int n = dailyValues.length;
>
> > for (int i = 0; i < n; i++)
> > {
> > sum = 1.0;
> > for (int j = i + 1; j < n; j++)
> > {
> > sum *= (1.0 + (totalValues[j] / 100.0));
> > }
>
> > contrib[i] = sum * dailyValues[i];
> > }
>
> > Many thanks for your help.
>
> > -- Shoeb
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