I want to add one more thing to what I said before ..
(identical? s1 s2)
would return false...
Sunil.

On Wed, Dec 1, 2010 at 11:26 AM, Sunil S Nandihalli <
[email protected]> wrote:

> Thanks ken for your response .. I think I completely misrepresented my
> question in my previous email . What i want to know is suppose I have two
> sets  s1,s2 and
> (= s1 s2)
>
> returns true which means I can definitely find pairs of values v1 from s1
> and v2 from s2 where
> (= v1 v2)
> would be true. Now my question is if I do a seq on both the sets s1 and s2
> would I be right in assuming that the ordering of the elements is identical
> or would even
> (identical? v1 v2)
> have to be true to have any guarantees on the orderings of the two seqs
> being the same...
>
> Thanks,
> Sunil
>
>
> On Wed, Dec 1, 2010 at 11:15 AM, Ken Wesson <[email protected]> wrote:
>
>> On Wed, Dec 1, 2010 at 12:35 AM, Sunil S Nandihalli
>> <[email protected]> wrote:
>> > Hello everybody,
>> >  I would like to know as to what I can assume about order of the
>> elements
>> > when I do a seq on hash-map or a set?
>>
>> Absolutely nothing. If you want arbitrary but controlled ordering, use
>> a vector or a seq. If you want to sort on a specific criterion that
>> can be computed from each element, use sorted-map, sorted-set,
>> sorted-map-by, sorted-set-by, or a seq view produced with sort or
>> sort-by.
>>
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>
>

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