Here is what I get:
(and BTW, my original version with #' seems to work, I'm a little bit
puzzled ...)

user=> (defn fib [n]
 (println "called with " n)
 (if (> n 2)
   (+ (fib (- n 2)) (fib (- n 1)))
   1))

(def fib (memoize fib))
#'user/fib
user=> user=> #'user/fib
user=> (fib 6)
called with  6
called with  4
called with  2
called with  3
called with  1
called with  2
called with  5
called with  3
called with  1
called with  2
called with  4
called with  2
called with  3
called with  1
called with  2
8
user=> (defn fib [n]
 (println "called with " n)
 (if (> n 2)
   (+ (#'fib (- n 2)) (#'fib (- n 1)))
   1))

(def fib (memoize fib))
#'user/fib
user=> user=> #'user/fib
user=> (fib 6)
called with  6
called with  4
called with  2
called with  3
called with  1
called with  5
8
user=>

2010/7/23 Paul Mooser <[email protected]>

> Why not simply do:
>
> (defn fib [n]
>  (println "called with " n)
>   (if (> n 2)
>    (+ (fib (- n 2)) (fib (- n 1)))
>    1))
>
> (def fib (memoize fib))
>
> I inserted the println to verify when we were actually calling the
> function, and I believe this works - fib only seems to get invoked a
> single time for any given n. Is this solution incorrect in some way?
>
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