On Tue, 29 Jun 2010 22:44:58 -0700 (PDT)
Tim Robinson <[email protected]> wrote:
> So I am reading On Lisp + some blogs while learning Clojure (I know,
> scary stuff :)
>
> Anyway, I've been playing around to see if I can get an anonymous
> recursive function to work, but alas I am still a n00b and not even
> sure what Clojure's approach to this would be.
> How would I do this in Clojure?:
IIUC based on examples involving label and letrec, you want a
recursive function whose name isn't visible outside of some restricted
scope. letfn is analogous to those, and that would look like:
(letfn [(anon [x]
(if (= x 0)
1
(* 2 (anon (dec x)))))]
(anon 5))
> My first attempt:
>
> ((fn [x]
> (if (= x 0)
> 1
> (* 2 (recur (dec z))))) 5)
>
> Then my second:
>
> ((fn [x]
> (let [z (if (= x 0)
> 1
> (* 2 x))]
> (recur (dec z)))) 5)
>
> Ideally one could do:
>
> ((recursive-fn #( if (= % 0) 1 (* 2 %)) (recur it)) 5)
>
>
> Obviously none work, and I believe I understand why. I just don't
> understand how to actually do this or if for some reason Clojure
> avoids this for some reason.
On the other hand, maybe I misunderstood what you're trying to do, in
which case an example of what you mean by "anonymous recursive
function" in another language (CL or Scheme by preference) would help.
<mike
--
Mike Meyer <[email protected]> http://www.mired.org/consulting.html
Independent Network/Unix/Perforce consultant, email for more information.
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